1/3(10^x+2)+4=16

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Solution for 1/3(10^x+2)+4=16 equation: 



1/3(10^x+2)+4=16

We move all terms to the left:

1/3(10^x+2)+4-(16)=0



Domain of the equation: 3(10^x+2)!=0

x∈R



We add all the numbers together, and all the variables

1/3(10^x+2)-12=0

We multiply all the terms by the denominator


-12*3(10^x+2)+1=0

Wy multiply elements

-36x(1+1=0

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